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A line passes through the points in this table. x y 4 17 5 4 6 -9 7 -22 What is the slope of the line? Write your answer as an...Asked by mav welborn
                A line passes through the points in this table.
x y
-5 29
0 22
15 1
25 -13
What is the slope of the line?
Write your answer as an integer or simplified fraction.
            
            
        x y
-5 29
0 22
15 1
25 -13
What is the slope of the line?
Write your answer as an integer or simplified fraction.
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To find the slope of the line that passes through the given points, we can use the slope formula, which is defined as:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
where \( (x_1, y_1) \) and \( (x_2, y_2) \) are any two points on the line.
Let's use the points \( (0, 22) \) and \( (25, -13) \) for our calculation.
Here, \( x_1 = 0 \), \( y_1 = 22 \), \( x_2 = 25 \), and \( y_2 = -13 \).
Now plug these values into the formula:
\[
m = \frac{-13 - 22}{25 - 0}
\]
Calculating the numerator:
\[
-13 - 22 = -35
\]
Calculating the denominator:
\[
25 - 0 = 25
\]
So now we have:
\[
m = \frac{-35}{25}
\]
This can be simplified. Both -35 and 25 can be divided by 5:
\[
m = \frac{-35 \div 5}{25 \div 5} = \frac{-7}{5}
\]
Therefore, the slope of the line is:
\[
\boxed{-\frac{7}{5}}
\]
    
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
where \( (x_1, y_1) \) and \( (x_2, y_2) \) are any two points on the line.
Let's use the points \( (0, 22) \) and \( (25, -13) \) for our calculation.
Here, \( x_1 = 0 \), \( y_1 = 22 \), \( x_2 = 25 \), and \( y_2 = -13 \).
Now plug these values into the formula:
\[
m = \frac{-13 - 22}{25 - 0}
\]
Calculating the numerator:
\[
-13 - 22 = -35
\]
Calculating the denominator:
\[
25 - 0 = 25
\]
So now we have:
\[
m = \frac{-35}{25}
\]
This can be simplified. Both -35 and 25 can be divided by 5:
\[
m = \frac{-35 \div 5}{25 \div 5} = \frac{-7}{5}
\]
Therefore, the slope of the line is:
\[
\boxed{-\frac{7}{5}}
\]
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