First, we need to find the slope of the line.
Slope (m) = (y2 - y1)/(x2 - x1)
m = (-3 - 15) / (1 - (-1))
m = (-18) / (2)
m = -9
Now that we have the slope, we can use the point-slope form of a linear equation to find the equation of the line:
y - y1 = m(x - x1)
Using the point (1, -3):
y - (-3) = -9(x - 1)
y + 3 = -9x + 9
Subtract 3 from both sides:
y = -9x + 6
Therefore, the equation of the line passing through the points (-1, 15) and (1, -3) in slope-intercept form is y = -9x + 6.
A line passes through the points (
–
1,15) and (1,
–
3). Write its equation in slope-intercept form.
Write your answer using integers, proper fractions, and improper fractions in simplest form.
1 answer
1 answer