P(2,-7), M(x,y), Q(-4.-1)
X = (x1+x2)/2 = (2+(-4))/2 = -1.
Y = (y1+y2)/2 = (-7+(-1))/2 = -4.
M(-1,-4)
A line in coordinate plane contains the points P(2, -7) and Q(-4, -1). What point is the midpoint of PQ?
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1 answer