A line has the equation 3x-30y-15=0.

Express the equation of the line in the form y=mx +c

1 answer

To express the equation of the line in the form y=mx +c, we need to isolate y on one side of the equation.

Starting with the given equation:

3x - 30y - 15 = 0

First, let's move -30y to the other side of the equation by adding 30y to both sides:

3x - 15 = 30y

Now, divide both sides by 30 to solve for y:

(3x - 15)/30 = y
y = (3/30)x - 15/30
y = (1/10)x - 1/2

So, the equation of the line in the form y=mx +c is y = (1/10)x - 1/2.