To find two points through which a line with a slope of -5/3 could pass, we can assign arbitrary values to one of the coordinates and solve for the other coordinate.
Let's assign an arbitrary value of x = 3 to one of the points.
If x = 3, then the line equation becomes y = (-5/3)(3) + b, where b is the y-intercept.
Simplifying this equation, we have y = -5 + b.
Now, we can choose a value for b and find the corresponding y-coordinate. Let's say b = 4.
Plugging these values into the equation, we have y = -5 + 4, which gives us y = -1.
Therefore, one point through which the line could pass is (3, -1).
To find another point, we can choose a different value for b. Let's say b = 0.
Plugging this value into the equation, we have y = -5 + 0, which gives us y = -5.
Therefore, the second point through which the line could pass is (3, -5).
So, the line with a slope of -5/3 could pass through the points (3, -1) and (3, -5).
A line has slope -5/3 Through which two points could this line pass
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