Since the $y$-intercept is $(0,b) = (0,2),$ this means that the line passes through the point $(0,2).$ Thus, the $x$-intercept must be $\boxed{1}.$
[asy]
unitsize(1 cm);
pair A, B, C;
A = (0,2);
B = (1,0);
C = (2,0);
draw((-0.5,0)--(2,0));
draw((0,-0.5)--(0,3));
draw(A--(B + C)/2);
label("$y = 2x + 2$", (2,3), NE);
dot("$(0,2)$", A, NW);
dot("$(1,0)$", B, SE);
[/asy]
A line has a slope of $m,$ and its $y$-intercept is $(0,b)$. If $m = 2$ and $b = 2,$ then what is the $x$-intercept of the line?
1 answer