Asked by gOt MiLk
A line has a slope of
–
5 and passes through the point (
–
4,
–
1). What is its equation in point-slope form?
–
5 and passes through the point (
–
4,
–
1). What is its equation in point-slope form?
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To write the equation of a line in point-slope form, you can use the formula:
\[
y - y_1 = m(x - x_1)
\]
where \( m \) is the slope of the line, and \((x_1, y_1)\) is a point on the line.
Given:
- Slope (\( m \)) = -5
- Point (\( x_1, y_1 \)) = (-4, -1)
Substituting these values into the formula:
\[
y - (-1) = -5(x - (-4))
\]
This simplifies to:
\[
y + 1 = -5(x + 4)
\]
Thus, the equation of the line in point-slope form is:
\[
y + 1 = -5(x + 4)
\]
\[
y - y_1 = m(x - x_1)
\]
where \( m \) is the slope of the line, and \((x_1, y_1)\) is a point on the line.
Given:
- Slope (\( m \)) = -5
- Point (\( x_1, y_1 \)) = (-4, -1)
Substituting these values into the formula:
\[
y - (-1) = -5(x - (-4))
\]
This simplifies to:
\[
y + 1 = -5(x + 4)
\]
Thus, the equation of the line in point-slope form is:
\[
y + 1 = -5(x + 4)
\]
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