To find the equation of the line that passes through the points \((-3, 2)\) and \((0, 2)\), we first need to determine the slope \(m\). The formula for the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Using the given points \((-3, 2)\) and \((0, 2)\):
\[ m = \frac{2 - 2}{0 - (-3)} = \frac{0}{3} = 0 \]
The slope \(m\) is 0, which means the line is horizontal.
In slope-intercept form (\(y = mx + b\)), since the slope \(m\) is 0, the equation simplifies to:
\[ y = 0 \cdot x + b \]
\[ y = b \]
To find \(b\), we use one of the given points. Plugging in the point \((0, 2)\):
\[ 2 = b \]
Thus, the equation of the line is:
\[ y = 2 \]
So, the answer is:
\[ \boxed{D. \, y = 2} \]
A line contains the points (-3, 2) and (0, 2). What is the equation of this line in slope-intercept form?
A. y = 3x + 2
B. y = –3x + 2
C. y = –3
D. y = 2
1 answer
1 answer