A light string is attached to both a hanging mass m1 = 5 kg and to a pulley of mass m2= 6 kg, and radius R = 0.75 m. If the pulley is a solid disc rotating about its center with a moment of inertia of I = 0.5*m2R2, and the string does not slip on the pulley,

Question

A light string is attached to both a hanging mass m1 = 5 kg and to a pulley of mass m2= 6 kg, and radius R = 0.75 m. If the pulley is a solid disc rotating about its center with a moment of inertia of I = 0.5*m2R2, and the string does not slip on the pulley, 
(a) what is the acceleration of mass 1? Assume g=10 m/s2

bobpursley · Answer

torque=m(g-a)*R=momentinertia*angular acceleratin but angular acceleration= ma*(2PI)/R solve for a. check my thinking