the force on each side of the spring is the same.
force=kx
Then, opposing that force is fricion on each side.
to the left, net force=kx-mu*.350*g
to the right, net force=kx-mu*.700*g
on the left= kx-mu*.350*9.8=.350*a where kx = 3*.06=.18N
on the right, kx-mu*.7*9.8=.7a
Remember, when friction is greater than kx, motion does not occur.
A light spring with force constant 3.00 N/m is compressed by 6.00 cm as it is held between a 0.350 kg block on the left and a 0.700 kg block on the right, both resting on a horizontal surface. The spring exerts a force on each block, tending to push them apart. The blocks are simultaneously released from rest. Find the acceleration with which each block starts to move, given that the coefficient of kinetic friction between each block and the surface is the following values. Let the coordinate system be positive to the right and negative to the left.
(a) µ = 0
heavier block __m/s2
lighter block __m/s2
(b) µ = 0.035
heavier block __m/s2
lighter block __m/s2
(c) µ = 0.462
heavier block __m/s2
lighter block __m/s2
1 answer
1 answer