A lead ball is dropped into a lake from a diving board 4.50 m above the water. After entering the water, it sinks to the bottom with a constant velocity equal to the velocity with which it hit the water. The ball reaches the bottom 4.40 s after it is released. How deep is the lake?

3 answers

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calulate speed after falling 4.5 m

(1/2) m v^2 = m g h
so
v = sqrt (2 g h)

then
v t = 4.4

now try the others