ΔT =34.3-19.3=15º
V=Vₒ(1+3•α•ΔT) =
=94.3•10^-6• (1+3•29•10^-6•15)=
=94.4•10^-6 m³=94.4 cm³.
A lead ball has a volume of 94.3 cm3 at 19.3°C. What is the change in volume when its temperature changes to 34.3°C?
1 answer
1 answer