A launched rocket has an altitude in meters, given by the polynomial h+vt-4.9^2, h is the height in meters v is the velocity in meters per second and t is the number of seconds for which it takes the rocket to become airborne. If the rocket is launched from the top of a tower that is 100 meters and the initial speed is 60 meters per second, what will its height be after 4 seconds rounded to the nearest tenth?

Answer 1

h = 100 + Vo*t + 0.5*gt^2.

h = 100 + 60*4 + 0.5*(-9.8)4^2,
h = 100 + 240 - 78.4 = 261.6m above ground.

h = 261.6 - 100 = 161.6m above the tower.