A launched rocket has an altitude, in meters, given by the polynomial h+vt-4.9t^2, where h is the height, in meters, from which the launch occurs, at the velocity v in meters per second, and the t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 150 meters high with an initial upward speed of 60 meters per second, what will its height be after 4 seconds?

Answer 1

h=150m
v=60m/s
t=4s
height of rocket=h+vt-4.9t^2
=150+(60x4)-4.9x4^2
=311.6m