Asked by Sam
A large tank is filled with water to a depth of d = 18 m. A spout located h = 13 m above the bottom of the tank is then opened as shown in the drawing. With what speed will water emerge from the spout?
Answers
Answered by
drwls
The pressure of water at the hole location is
P = (rho)gH + Po
where Po is atmospheric pressure
The Bernoulli equation tells you that
(1/2)(rho) V^2 = P - Po = (rho) g H
The water density (rho) cancels out, so
V = sqrt (2 g H)
H is this case the the height of water ABOVE the hole, which is 5 m, not h=13 m
P = (rho)gH + Po
where Po is atmospheric pressure
The Bernoulli equation tells you that
(1/2)(rho) V^2 = P - Po = (rho) g H
The water density (rho) cancels out, so
V = sqrt (2 g H)
H is this case the the height of water ABOVE the hole, which is 5 m, not h=13 m
Answered by
Rob
9.8
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