A large container, 114 cm deep is filled with water. If a small hole is punched in its side 93.0 cm from the top, at what initial speed will the water flow from the hole?
3 answers
SAAAME
Mass of water that escapes per unit time
= m
Since the mass of water drops in height by an equivalent of h=1.14 m, we can equate change in energy = 0,
or
mgh-(1/2)mv^2=0
Solve for v
= m
Since the mass of water drops in height by an equivalent of h=1.14 m, we can equate change in energy = 0,
or
mgh-(1/2)mv^2=0
Solve for v
v=(2hg)^1/2
v=(2*93*980)^1/2
v=426.9cm=4.269m
v=(2*93*980)^1/2
v=426.9cm=4.269m
1 answer