A large company wants to find out what team-building activity its employees prefer. Which of the following samples can give the most valid generalization?(1 point)
all employees who have worked in the company for 5 years or more
all employees who have worked in the company for 5 years or more
a group with one member from each department
a group with one member from each department
all 624 female employees in the company
all 624 female employees in the company
400 randomly chosen employees from the list of all employees
11 answers
400 randomly chosen employees from the list of all employees
A hotel maintenance crew wants to estimate how many of the 12,000 lamps in their 30-story hotel need a new light bulb. Which of the following is a random sample of lamps to be inspected?(1 point)
all lamps from the rooms with king-sized beds
all lamps from the rooms with king-sized beds
all lamps in booked rooms
all lamps in booked rooms
400 lamps on the first 10 floors
400 lamps on the first 10 floors
100 lamps on each floor chosen randomly
100 lamps on each floor chosen randomly
all lamps from the rooms with king-sized beds
all lamps from the rooms with king-sized beds
all lamps in booked rooms
all lamps in booked rooms
400 lamps on the first 10 floors
400 lamps on the first 10 floors
100 lamps on each floor chosen randomly
100 lamps on each floor chosen randomly
100 lamps on each floor chosen randomly
A local library manager randomly surveys 80 patrons about the type of book they borrow when they visit the library. The manager finds that 3 patrons borrow novels. If the local library has 345 patrons, approximately how many of them borrow novels when they visit the library? Round your answer to the nearest whole number. (1 point)
To estimate the number of patrons who borrow novels when they visit the library, we can set up a proportion using the sample data.
3 patrons out of 80 surveyed borrow novels.
Let x represent the total number of patrons who borrow novels out of the total of 345 patrons:
3/80 = x/345
Cross multiply:
80x = 3 * 345
80x = 1035
Divide both sides by 80 to solve for x:
x ≈ 12.94
Rounded to the nearest whole number, approximately 13 patrons out of the total 345 patrons are estimated to borrow novels when they visit the library.
3 patrons out of 80 surveyed borrow novels.
Let x represent the total number of patrons who borrow novels out of the total of 345 patrons:
3/80 = x/345
Cross multiply:
80x = 3 * 345
80x = 1035
Divide both sides by 80 to solve for x:
x ≈ 12.94
Rounded to the nearest whole number, approximately 13 patrons out of the total 345 patrons are estimated to borrow novels when they visit the library.
The table shows the times, in minutes, spent shopping by two different groups. First find the mean times each group spent shopping. Then determine the difference in the mean times. Round your answers to one decimal place.(2 points)
To find the mean times each group spent shopping, we first need to calculate the sum of the shopping times for each group and then divide by the number of data points.
1. For Group A:
Sum of shopping times = 12 + 15 + 17 + 21 + 23 = 88 minutes
Number of data points = 5
Mean time for Group A = Sum of shopping times / Number of data points
Mean time for Group A = 88 / 5 = 17.6 minutes
2. For Group B:
Sum of shopping times = 10 + 13 + 18 + 22 + 25 = 88 minutes
Number of data points = 5
Mean time for Group B = Sum of shopping times / Number of data points
Mean time for Group B = 88 / 5 = 17.6 minutes
Now, we will determine the difference in the mean times:
Difference in mean times = Mean time for Group A - Mean time for Group B
Difference in mean times = 17.6 - 17.6 = 0 minutes
Therefore, the mean shopping times for both groups are 17.6 minutes each, and the difference in mean times is 0 minutes.
1. For Group A:
Sum of shopping times = 12 + 15 + 17 + 21 + 23 = 88 minutes
Number of data points = 5
Mean time for Group A = Sum of shopping times / Number of data points
Mean time for Group A = 88 / 5 = 17.6 minutes
2. For Group B:
Sum of shopping times = 10 + 13 + 18 + 22 + 25 = 88 minutes
Number of data points = 5
Mean time for Group B = Sum of shopping times / Number of data points
Mean time for Group B = 88 / 5 = 17.6 minutes
Now, we will determine the difference in the mean times:
Difference in mean times = Mean time for Group A - Mean time for Group B
Difference in mean times = 17.6 - 17.6 = 0 minutes
Therefore, the mean shopping times for both groups are 17.6 minutes each, and the difference in mean times is 0 minutes.
Use the table to answer the question.
Group A 18 20 46 34 58 31 41
Group B 15 21 32 42 29 57 39The table shows the times, in minutes, spent shopping by two different groups. First find the mean times each group spent shopping. Then determine the difference in the mean times. Round your answers to one decimal place.(2 points)
The mean time Group A spent shopping is
minutes.
The mean time Group B spent shopping is
minutes.
The mean times Group A and Group B spent shopping differ by
minutes.
Group A 18 20 46 34 58 31 41
Group B 15 21 32 42 29 57 39The table shows the times, in minutes, spent shopping by two different groups. First find the mean times each group spent shopping. Then determine the difference in the mean times. Round your answers to one decimal place.(2 points)
The mean time Group A spent shopping is
minutes.
The mean time Group B spent shopping is
minutes.
The mean times Group A and Group B spent shopping differ by
minutes.
To find the mean times each group spent shopping, we first calculate the sum of the shopping times for each group and then divide by the number of data points.
1. For Group A:
Sum of shopping times for Group A = 18 + 20 + 46 + 34 + 58 + 31 + 41 = 248 minutes
Number of data points for Group A = 7
Mean time for Group A = Sum of shopping times / Number of data points
Mean time for Group A = 248 / 7 ≈ 35.4 minutes
2. For Group B:
Sum of shopping times for Group B = 15 + 21 + 32 + 42 + 29 + 57 + 39 = 235 minutes
Number of data points for Group B = 7
Mean time for Group B = Sum of shopping times / Number of data points
Mean time for Group B = 235 / 7 ≈ 33.6 minutes
Now, we will determine the difference in the mean times:
Difference in mean times = Mean time for Group A - Mean time for Group B
Difference in mean times = 35.4 - 33.6 = 1.8 minutes
Therefore,
The mean time Group A spent shopping is approximately 35.4 minutes
The mean time Group B spent shopping is approximately 33.6 minutes
The mean times Group A and Group B spent shopping differ by approximately 1.8 minutes.
1. For Group A:
Sum of shopping times for Group A = 18 + 20 + 46 + 34 + 58 + 31 + 41 = 248 minutes
Number of data points for Group A = 7
Mean time for Group A = Sum of shopping times / Number of data points
Mean time for Group A = 248 / 7 ≈ 35.4 minutes
2. For Group B:
Sum of shopping times for Group B = 15 + 21 + 32 + 42 + 29 + 57 + 39 = 235 minutes
Number of data points for Group B = 7
Mean time for Group B = Sum of shopping times / Number of data points
Mean time for Group B = 235 / 7 ≈ 33.6 minutes
Now, we will determine the difference in the mean times:
Difference in mean times = Mean time for Group A - Mean time for Group B
Difference in mean times = 35.4 - 33.6 = 1.8 minutes
Therefore,
The mean time Group A spent shopping is approximately 35.4 minutes
The mean time Group B spent shopping is approximately 33.6 minutes
The mean times Group A and Group B spent shopping differ by approximately 1.8 minutes.
Which data set has the highest median?(1 point)
{11, 15, 16, 8, 12, 14}
left brace 11 comma 15 comma 16 comma 8 comma 12 comma 14 right brace
{8, 20, 13, 14, 12, 9}
left brace 8 comma 20 comma 13 comma 14 comma 12 comma 9 right brace
{1, 10, 8, 29, 14, 17, 3}
left brace 1 comma 10 comma 8 comma 29 comma 14 comma 17 comma 3 right brace
{1, 6, 15, 7, 15, 18, 14}
{11, 15, 16, 8, 12, 14}
left brace 11 comma 15 comma 16 comma 8 comma 12 comma 14 right brace
{8, 20, 13, 14, 12, 9}
left brace 8 comma 20 comma 13 comma 14 comma 12 comma 9 right brace
{1, 10, 8, 29, 14, 17, 3}
left brace 1 comma 10 comma 8 comma 29 comma 14 comma 17 comma 3 right brace
{1, 6, 15, 7, 15, 18, 14}
To determine which data set has the highest median, we need to first evaluate the medians of the given data sets.
1. Data set {11, 15, 16, 8, 12, 14}:
Arranging the data in ascending order: 8, 11, 12, 14, 15, 16
The median of this data set is the middle value, which is 14.
2. Data set {8, 20, 13, 14, 12, 9}:
Arranging the data in ascending order: 8, 9, 12, 13, 14, 20
The median of this data set is the average of the two middle values, which are 12 and 13. Therefore, the median is (12 + 13) / 2 = 12.5.
3. Data set {1, 10, 8, 29, 14, 17, 3}:
Arranging the data in ascending order: 1, 3, 8, 10, 14, 17, 29
The median of this data set is the middle value, which is 10.
4. Data set {1, 6, 15, 7, 15, 18, 14}:
Arranging the data in ascending order: 1, 6, 7, 14, 15, 15, 18
The median of this data set is the average of the two middle values, which are 14 and 15. Therefore, the median is (14 + 15) / 2 = 14.5.
Based on the calculated medians:
- {11, 15, 16, 8, 12, 14} has a median of 14
- {8, 20, 13, 14, 12, 9} has a median of 12.5
- {1, 10, 8, 29, 14, 17, 3} has a median of 10
- {1, 6, 15, 7, 15, 18, 14} has a median of 14.5
Therefore, the data set {1, 6, 15, 7, 15, 18, 14} has the highest median of 14.5.
1. Data set {11, 15, 16, 8, 12, 14}:
Arranging the data in ascending order: 8, 11, 12, 14, 15, 16
The median of this data set is the middle value, which is 14.
2. Data set {8, 20, 13, 14, 12, 9}:
Arranging the data in ascending order: 8, 9, 12, 13, 14, 20
The median of this data set is the average of the two middle values, which are 12 and 13. Therefore, the median is (12 + 13) / 2 = 12.5.
3. Data set {1, 10, 8, 29, 14, 17, 3}:
Arranging the data in ascending order: 1, 3, 8, 10, 14, 17, 29
The median of this data set is the middle value, which is 10.
4. Data set {1, 6, 15, 7, 15, 18, 14}:
Arranging the data in ascending order: 1, 6, 7, 14, 15, 15, 18
The median of this data set is the average of the two middle values, which are 14 and 15. Therefore, the median is (14 + 15) / 2 = 14.5.
Based on the calculated medians:
- {11, 15, 16, 8, 12, 14} has a median of 14
- {8, 20, 13, 14, 12, 9} has a median of 12.5
- {1, 10, 8, 29, 14, 17, 3} has a median of 10
- {1, 6, 15, 7, 15, 18, 14} has a median of 14.5
Therefore, the data set {1, 6, 15, 7, 15, 18, 14} has the highest median of 14.5.