A large company wants to find out what team-building activity its employees prefer. Which of the following samples can give the most valid generalization?(1 point)

Responses

400 randomly chosen employees from the list of all employees
400 randomly chosen employees from the list of all employees

a group with one member from each department
a group with one member from each department

all employees who have worked in the company for 5 years or more
all employees who have worked in the company for 5 years or more

all 624 female employees in the company

9 answers

400 randomly chosen employees from the list of all employees
A hotel maintenance crew wants to estimate how many of the 12,000 lamps in their 30-story hotel need a new light bulb. Which of the following is a random sample of lamps to be inspected?(1 point)
Responses

400 lamps on the first 10 floors
400 lamps on the first 10 floors

all lamps in booked rooms
all lamps in booked rooms

all lamps from the rooms with king-sized beds
all lamps from the rooms with king-sized beds

100 lamps on each floor chosen randomly
100 lamps on each floor chosen randomly
A local library manager randomly surveys 80 patrons about the type of book they borrow when they visit the library. The manager finds that 3 patrons borrow novels. If the local library has 345 patrons, approximately how many of them borrow novels when they visit the library? Round your answer to the nearest whole number. (1 point)
patrons
To estimate how many of the 345 patrons borrow novels, we can set up a proportion using the information from the survey:

3 patrons out of the 80 surveyed borrowed novels. Let's set it up as a proportion:

3/80 = x/345

Cross multiply to solve for x:

80x = 3 * 345
80x = 1035
x = 1035 / 80
x = 12.9375

Rounded to the nearest whole number, approximately 13 of the 345 patrons would be expected to borrow novels when they visit the library.
The table shows the times, in minutes, spent shopping by two different groups. First find the mean times each group spent shopping. Then determine the difference in the mean times. Round your answers to one decimal place.(2 points)
The mean time Group A spent shopping is
minutes.
The mean time Group B spent shopping is
minutes.
The mean times Group A and Group B spent shopping differ by
minutes.
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Since the table providing the times spent shopping is not included in the question, I will provide an example calculation based on hypothetical data for Group A and Group B.

Assuming the times spent shopping for Group A are: 13, 25, 18, 20, and 22 minutes.
And the times spent shopping for Group B are: 10, 15, 24, 19, and 20 minutes.

First, calculate the mean times for each group:
For Group A:
Mean = (13 + 25 + 18 + 20 + 22) / 5
Mean = 98 / 5
Mean = 19.6 minutes for Group A

For Group B:
Mean = (10 + 15 + 24 + 19 + 20) / 5
Mean = 88 / 5
Mean = 17.6 minutes for Group B

Now, find the difference in the mean times:
Difference = Mean of Group A - Mean of Group B
Difference = 19.6 - 17.6
Difference = 2 minutes

Therefore, based on the hypothetical data provided, the mean time Group A spent shopping is 19.6 minutes, the mean time Group B spent shopping is 17.6 minutes, and the mean times Group A and Group B spent shopping differ by 2 minutes.
Which data set has the highest median?(1 point)
Responses

{8, 20, 13, 14, 12, 9}
left brace 8 comma 20 comma 13 comma 14 comma 12 comma 9 right brace

{11, 15, 16, 8, 12, 14}
left brace 11 comma 15 comma 16 comma 8 comma 12 comma 14 right brace

{1, 10, 8, 29, 14, 17, 3}
left brace 1 comma 10 comma 8 comma 29 comma 14 comma 17 comma 3 right brace

{1, 6, 15, 7, 15, 18, 14}
To determine which data set has the highest median, we need to find the median of each set of numbers and compare them.

1. For the first set {8, 20, 13, 14, 12, 9}:
- Arranging the numbers in ascending order: {8, 9, 12, 13, 14, 20}
- The median is the middle value, which is 13.

2. For the second set {11, 15, 16, 8, 12, 14}:
- Arranging the numbers in ascending order: {8, 11, 12, 14, 15, 16}
- The median is the average of the two middle values, (12 + 14) / 2 = 13.

3. For the third set {1, 10, 8, 29, 14, 17, 3}:
- Arranging the numbers in ascending order: {1, 3, 8, 10, 14, 17, 29}
- The median is 10.

4. For the fourth set {1, 6, 15, 7, 15, 18, 14}:
- Arranging the numbers in ascending order: {1, 6, 7, 14, 15, 15, 18}
- The median is the average of the two middle values, (7 + 14) / 2 = 10.5.

Based on these calculations, the first data set {8, 20, 13, 14, 12, 9} has the highest median of 13.