A large chocolate chip cookie weighs 5/6 ounce, and a small chocolate chip cookie weighs 4/9 ounce. How much more does the large cookie weigh than the small cookie?

Question

Responses

Answer 1

To find out how much more the large cookie weighs than the small cookie, you need to subtract the weight of the small cookie from the weight of the large cookie.

The weight of the large cookie is \( \frac{5}{6} \) ounce, and the weight of the small cookie is \( \frac{4}{9} \) ounce.

To subtract these two fractions, you first need a common denominator. The least common multiple of 6 and 9 is 18.

Now, convert each fraction to have a denominator of 18:

1. Convert \( \frac{5}{6} \): \[ \frac{5}{6} = \frac{5 \times 3}{6 \times 3} = \frac{15}{18} \]

2. Convert \( \frac{4}{9} \): \[ \frac{4}{9} = \frac{4 \times 2}{9 \times 2} = \frac{8}{18} \]

Now, subtract the two fractions: \[ \frac{15}{18} - \frac{8}{18} = \frac{15 - 8}{18} = \frac{7}{18} \]

So, the large cookie weighs \( \frac{7}{18} \) ounce more than the small cookie.