A landscaping company placed two orders with a nursery. The first order was for 13 bushes and 4 trees, and totaled $487.00. The second was for 6 bushes and 2 trees, and totaled $232.00. The bills do not list the per-item price. What were the costs of one bush and of one tree?

Answer 1

Looks like algebra I to me. Anyway,

(1) 13b+4t = 487
(2) 6b+2t = 232
Subtracting twice #2 from #1 we get
b = 23
so, t = 47

b+t = 70

Answer 2

c=15+10h
c=8h