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A landowner wants to fence in a rectangular area of 75000 square metres and divide it into three parts with two parallel fences...Asked by ryan
A landowner wants to fence in a rectangular area of 60000 square metres and divide it into three parts with two parallel fences both parallel to one side of the rectangle. Each part will have a different grazing crop for the herds. What is the shortest total length of fence that he can use?
Answers
Answered by
Steve
as usual, divide the fencing equally among lengths and widths. So, I'll go ahead and predict that the solution will be
7500 x 15000
7500 x 15000
Answered by
Steve
oops. wrong problem.
y = 60000/x
p = 2x+4y = 2x + 4(60000/x)
dp/dx=0 when x=200√3 and y=100√3
p = 800√3
But, as usual, the length is equally divided among lengths and widths.
y = 60000/x
p = 2x+4y = 2x + 4(60000/x)
dp/dx=0 when x=200√3 and y=100√3
p = 800√3
But, as usual, the length is equally divided among lengths and widths.
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