if the ladder reaches up h feet,
sinθ = h/10
cosθ dθ/dt = 1/10 dh/dt
You know θ and dh/dt, so solve for dθ/dt.
a ladder of 10 ft long leans against a vertical wall. the upper end slips down the wall at 5 ft/sec. how fast is the ladder turning when it takes an angle of 30 degree with the ground?
2 answers
dθ/dt = sqrt(3)/3