a kite has 120 m of string attached to it when it flies at an elevation of 5 degrees. How far is it above the hand holding it? ( assume that the string is taut)
2 answers
sin 5 = h/120
sin5=h/120
h=sin5*120
h=0.0872*120
h=10.46
h=sin5*120
h=0.0872*120
h=10.46