If the two top pieces are 5 units each, the bottom pieces are 12 units each, and if the center piece is 13 inches each, you are looking at two right-angled triangles, since
5^2 + 12^2 = 13^2
Thus the length of the cross pieces is fixed as well as the area. So this is not a problem dealing with "maximum" area
the area of each of the two right-angled triangles is
(1/2)(5)12) = 30
so the area of the whole kite is 60 square units
let each height of the triangles be h
(1/2)(13)h = 30
h = 60/13
so the cross piece is 120/13 units long
A kite frame is to be made from 6 pieces of wood. The four border pieces have been cut 5 and 12. The long center piece is 13. what should the length of the cross pieces be in order to maximize the area of the kite.
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