A kiosk sells tokiwado in three flavours - chocolate, red bean and peanut at $3.50, $3 and $2.90 respectively. Each day, the number of pieces of chocolate tokiwado sold is 15 more than the number of pieces of red bean tokiwado sold and thrice the number of pieces of peanut tokiwado sold. Given that the kiosk collects $179 from their daily sale, how manv pieces of tokiwado do they sell daily?

Answer 1

Let's represent the number of red bean tokiwado pieces sold as x.
Then, the number of chocolate tokiwado pieces sold is x + 15, and the number of peanut tokiwado pieces sold is (x + 15)/3.

The total cost of red bean tokiwado sold is $3x.
The total cost of chocolate tokiwado sold is $3.50(x + 15) = $3.50x + $52.50.
The total cost of peanut tokiwado sold is $2.90[(x + 15)/3] = ($2.90/3)x + $2.90*5 = ($0.9667)x + $14.50.

The total sale collected is $3x + $3.50x + $52.50 + ($0.9667)x + $14.50 = $179.
Combining like terms, we get $4.4667x + $67 = $179.
Subtracting $67 from both sides, we have $4.4667x = $112.
Dividing both sides by $4.4667, we get x = 25.

So, the number of red bean tokiwado pieces sold is 25.
The number of chocolate tokiwado pieces sold is 25 + 15 = 40.
The number of peanut tokiwado pieces sold is (25 + 15)/3 = 10.

Therefore, they sell 25 + 40 + 10 = <<25+40+10=75>>75 pieces of tokiwado daily. Answer: \boxed{75}.