A kicker punts a football from 3 feet above the ground with an initial velocity of 47 feet per second.

Write an equation that gives the height (in feet) of the football as a function of the time (in seconds) since it was punted.

Find the height (in feet) of the football 2 seconds after the punt.

Calculate how many seconds after the punt the ball would hit the ground.

1 answer

height = -16t^2 + 47t + 3

when t=2
height = -64 + 94 + 3 = 33 feet high

to hit the ground, height = 0
-16t^2 + 47t+3=0
16t^2 - 47t - 3 = 0
(t-3)(16t + 1) = 0
t = 3 or t = a negative, which is not valid

it will hit the ground after 3 seconds