To find the charge per class and the monthly membership fee, we can set up a system of equations based on the provided data.
Let:
- \( M \) = monthly membership fee
- \( C \) = charge per class
We have the following data points based on the number of classes and total cost:
- For 1 class: \( M + 1C = 36 \)
- For 5 classes: \( M + 5C = 60 \)
- For 8 classes: \( M + 8C = 78 \)
- For 14 classes: \( M + 14C = 114 \)
- For 20 classes: \( M + 20C = 150 \)
We can use the first two equations to find \( M \) and \( C \).
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From the first equation: \[ M + 1C = 36 \quad \text{(i)} \]
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From the second equation: \[ M + 5C = 60 \quad \text{(ii)} \]
Now we can subtract equation (i) from equation (ii): \[ (M + 5C) - (M + 1C) = 60 - 36 \] This simplifies to: \[ 4C = 24 \] Now, divide both sides by 4: \[ C = 6 \]
Now that we have \( C \), we can substitute it back into equation (i) to find \( M \): \[ M + 1(6) = 36 \] This simplifies to: \[ M + 6 = 36 \] Subtracting 6 from both sides gives: \[ M = 30 \]
Thus, the monthly membership fee \( M \) is 30, and the charge per class \( C \) is 6.
Answer: Charge per class \( C = 6 \)