A juggler tosses a ball h = 2 m into the air with one hand and catches it with the other hand at the same level. Neglecting air resistance, how long is the ball in the air?

Answer 1

0.5g*t^2 = 2
4.9t^2 = 2
t^2 = 0.408
Tf = 0.639 s. = Fall time.

Tr = Tf = 0.639 s. = Rise time.

Tr+Tf = 0.639 + 0.639 = 1.28 s. = Time
in air.