A juggler performs in a room with a ceiling 2m abouve hand level. A. what is the maximum upward speed she can give the ball without hitting the celing.

Question

B. what is the time spent in the air before the ball is caught?

Answer 1

A.
Equate potential and kinetic energies:
potential energy = mgh = mg(2) N-m
where g = acceleration due to gravity = 9.8 m/s²
kinetic energy = (1/2)mv²

Equate energies:
mgh = (1/2)mv²
solve for v (m/s)

B. t = v/g (deceleration by gravity)

Answer 2

(A) 6.3m/s
(B)1.3 s