X = ?
Y = -2.9 km.
R = 4.25 km = Resultant.
X^2 + Y^2 = R^2
X^2 + (-2.9)^2 = (4.25)^2
X^2 = (4.25)^2 - (-2.9)^2 = 9.653
X = 3.1 km
tanA = -2.9/3.1 = -0.93548
A = -43.1 o
A = -43.1 + 360 = 316.9o CCW.
A = 316.9 - 270 = 46.9o East of South.
A jogger travels a route that has two parts. The first is a displacement of 2.90 km due south, and the second involves a displacement that points due east. The resultant displacement + has a magnitude of 4.25 km. (a) What is the magnitude of , and what is the direction of + as a positive angle relative to due south? (b) Suppose that - had a magnitude of 4.25 km. What then would be the magnitude of , and what is the direction of - relative to due south?
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1 answer