salary 1st year = 35000
salary 2nd year = 35000(1.04)
salary 3rd year = 35000(1.04)^2
...
salary 11th year = 3500(1.04)^10 = 51,808.55
sum of 11 terms of this GS
a = 35000
r = 1.04
sum(11) = a(r^11 - 1)/(r-1)
= 35000( 1.04^11 - 1)/(1.04 - 1) = 472,022.30
A job pays a salary of 35,000 the first year. During the next 10 years, the salary increases by 4% each year. What is the salary for the 11th year? What is the total salary over the 11 year period? (Round to the nearest cent.)
1 answer
1 answer