A jeweler has three solid gold cylinders with radii 2.0 millimeters, 3.0 millimeters, and 4.0 millimeters. Each cylinder

has a height of 10.0 millimeters. If the jeweler melts the cylinders down to make a solid prism with a square base of
length 5.0 millimeters, what will be the approximate height of the prism? Round to the nearest tenth.

1 answer

the total volumes of the cylinders must equal the volume of the prism, so
π(2^2 + 3^2 + 4^2)*10 = 5^2 * h
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