V = a * t ,
101 m/s = 4.60 m/s^2 * t,
t = 101/4.6 = 22 s.
b. d = 0.5 * a * t^2 = 0.5 * 4,6 m/s^2
* (22 s)^2 = 1113 m = 1.113 km.
a jet plane lands with a speed of 101 m/s and can accelerate at a maximum rate of -4.60 m/s2 as it comes to rest.
(a) From the instant the plane touches the runway, what is the minimum time needed before it can come to rest?
___s
b)What is the actual minimum distance needed to stop the plane?
___km
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2 answers