The horizontal component of the lift L is the centripetal force that holds
the plane in the circle.
L•sinφ = m•v²/R.
The vertical component of the lift supports the weight of the plane; therefore,
L•cosφ = m•g.
Dividing the first equation by the second gives
L•sinφ/ L•cosφ = tanφ =
= m•v²/ m•g •R =v²/ g •R =
= 106²/9.8•3810 =0.3
φ=16.75º.
L = m•g/cosφ =
= 2.4•10^5•9.8/cos16.75º=2.46•10^6 N
A jet flying at 106 m/s banks to make a horizontal circular turn. The radius of the turn is 3810 m, and the mass of the jet is 2.40 × 105 kg. Calculate the magnitude of the necessary lifting force.
Would I use the equation Fc=mv^2 / r ??
1 answer
1 answer