add the two vectors.
369E + 985(sin69deg N + cos69 E)
combine the like directions
E (369+353) + 989N
magnitude= sqrt(989^2 + 722^2)=....
A jet airliner moving initially at 369 mph
(with respect to the ground) to the east moves
into a region where the wind is blowing at
985 mph in a direction 69◦
north of east.
What is the new speed of the aircraft with
respect to the ground?
Answer in units of mph.
Please help me i tried so many times and i keep getting it wrong
1 answer