E=BxV where the important part of B is that which is perpendicular to v.
In general, the solution would be
emf=80E-6T*25m*300m/s*sinTheta, where theta is the angle below the horizon (assuming the plane is flying level). If in this case, the plane is flying due south say at the equator, and the magnetic field at the equator is parallel with the planes path, zero potential. So, more information on the inclination of the Magnetic field is needed.
A jet aircraft is flying due south at 300 m/s at a place where the earth’s magnetic field is 80 µT. Find the potential difference between the wing tips if they are 25 m apart. Which tip has the higher potential?
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