The probability of selecting a red marble on the first draw is 4/15 (4 red marbles out of 15 total marbles in the jar).
Since the first marble is not replaced, there are now 14 marbles left in the jar. If we want to select another red marble, there are now only 3 red marbles left out of the remaining 14. So the probability of selecting a red marble on the second draw given that the first marble was red is 3/14.
To find the probability of both events happening (selecting a red marble followed by another red marble), we need to multiply the two probabilities:
(4/15) x (3/14) = 2/105
Therefore, the probability of selecting a red marble followed by another red marble is 2/105.
A jar has 4 red marbles, 6 blue marbles, and and 5 green marbles. you select two marbles at random. one marble is drawn and not replaced. then a second marbel is drawn. what is the probability of selecting a red marble then another red mrble
3 answers
2/105 simplified
2/105 is already in its simplest form as the numerator 2 and the denominator 105 do not have any common factors other than 1.