To calculate the probability of both selected marbles being red, we need to find the probability of selecting a red marble first and then the probability of selecting another red marble without replacement.
The probability of selecting a red marble on the first pick is 3 red marbles out of a total of 9 marbles (6 blue + 3 red) = 3/9 = 1/3.
After selecting a red marble on the first pick, there are now 8 marbles left (2 red marbles and 6 blue marbles), so the probability of selecting another red marble on the second pick is 2 red marbles out of a total of 8 marbles = 2/8 = 1/4.
The probability of both selected marbles being red is the product of the probabilities of each event happening:
(1/3) * (1/4) = 1/12 ≈ 0.083
Therefore, the probability of both selected marbles being red is approximately 0.083 or 8.3%.
a jar contaiins six blue marbles and three red marbles suppose you choose a marbale at random and do not replace it then you choose a second marble find the probability of the following event both of the selected marbles are red round three decimal places
1 answer