To find the probability of both selected marbles being red, we need to find the probability of selecting a red marble for the first draw and then for the second draw without replacement.
There are 3 red marbles out of a total of 9 marbles in the jar.
Probability of selecting a red marble on the first draw = 3/9 = 1/3
Since we do not replace the marble, there are now only 2 red marbles left out of 8 total marbles.
Probability of selecting a red marble on the second draw = 2/8 = 1/4
Therefore, the probability of both selected marbles being red is:
(1/3) * (1/4) = 1/12
So, the probability of both selected marbles being red is 1/12.
a jar contaiins six blue marbles and three red marbles suppose you choose a marbale at random and do not replace it then you choose a second marble find the probability of the following event both of the selected marbles are red
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