A jack has a lever arm of 45cm and pitch of 0.5cm. If it's efficiency is 30%,what force is required to lift a load W of mass 1200kg
3 answers
final force needed = [1200 *9.81 / 0.30](.5/45)
Can you please drop the formula. Quite confuse.
the mechanical advantage is ... (2 π 45) / .5
the weight of the load is ... 1200 g
the efficiency means that the mechanical advantage is reduced
... by 70% in this case
force needed ... (1200 g) / (4 π * 45 * .30)
the weight of the load is ... 1200 g
the efficiency means that the mechanical advantage is reduced
... by 70% in this case
force needed ... (1200 g) / (4 π * 45 * .30)
3 answers