2HCl + X2CO3 ==> H2O + CO2 + 2XCl
mols HCl = g/molar mass = 7.3/36.5 = ?
M HCl = mols/dm3 = about 0.2
In the titration,
mols HCl = 0.00281 x 0.2 = ?
mols X2CO3 = 1/2 that from the coefficients
M X2CO3 = mols X2CO3/25 = ?
A is a solution of HCL containing 7.30g/dm3.B is a solution ofX2CO3 containing 10.6g/dm3.assume that average volume of acid is 2.81cm3 and the volume of base is 25.00cm3.from your result and information .calculate (I)concentration of A in mol/dm3(ii)concentration of B in mol/dm3 (H-1.00 cl-35.5 O-16.00 C-12.0
2 answers
A is a solution of HCI containing 7.30g /dm3. B is a solution of X2CO3 containing 10.6g/dm3. Put A into burette and titrate against 25 portions of B using methyl orange. Tabulated your burette readings and calculate the average volume of A used. The equation
for the reaction involved in the titration is X2CO3 +HCI - 2XCl +H2O +CO2
C from your result and information provided above, calculate the ; concentration of A in mole/dm3
Concentration of B in mole/dm3
Molar mass of X2CO3 (HCl +36.5g/dm3
for the reaction involved in the titration is X2CO3 +HCI - 2XCl +H2O +CO2
C from your result and information provided above, calculate the ; concentration of A in mole/dm3
Concentration of B in mole/dm3
Molar mass of X2CO3 (HCl +36.5g/dm3
2 answers