6HCl+2Al>>2AlCl3 + 3 H2
so 2 moles of Al reacts with 6 moles HCl
moles Al=1.35/27 so you need 6/2 * 1.35/27 moles Hcl=5.55 grams HCl
5.55=.28*1.14*Volume
solve for volume in mL
A hydrochloric acid solution consist of 28.0% HCl, by mass, and has a density of 1.14 g/mL. What
volume of this solution is required to react with 1.35 g Al?
2 answers
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