A hydraulic lift system has an input piston with an area of 0,5 m2 and an output piston whith an area of 2 m2.
What force is needes to lift a load of 1000 N?
3 answers
0.001
F2= A1 ÷A2 times F1
= 2m÷ 0.5 times 1000N
= 4 times 1000N
= 4000N
= 2m÷ 0.5 times 1000N
= 4 times 1000N
= 4000N
F1= F2*A1/A2
= 1000N*0.5/2= 250N
= 1000N*0.5/2= 250N
1 answer