A husband and wife discover that there is a 10% probability of their passing on a hereditary disease to any child they have. If they plan to have three children, what is the probability of the event that at least one child will inherit the disease?

Answer 1

.25*.25*.25=.0156

Answer 2

1-.1=.9

(.9)^3 =.729

1-.729= .271 or 27.1%