To find the final velocity of the hummingbird, we can use the following kinematic equation:
v_f = v_i + at
Where:
v_f = final velocity
v_i = initial velocity
a = acceleration
t = time
Given:
v_i = 12.0 m/s [N]
a = unknown
t = 25.0 s
First, let's calculate the acceleration using the formula:
a = (v_f - v_i) / t
We are trying to find the final velocity, so let's rearrange the formula to solve for acceleration:
a = (v_f - 12.0) / 25.0
Since the hummingbird starts at rest and has an initial velocity of 12.0 m/s [N], the final velocity at the end of 25.0 seconds will be:
450m = 0*25 + (1/2)a(25)^2
a= 450/625
v_f = 12.0 + (450/625)*25
v_f = 12.0 + 18.0
v_f = 30.0 m/s
Therefore, the bird's final velocity as it reaches the next flower is 30.0 m/s [N].
a hummingbird with an initial velocity of 12.0m/s [N] flies 450m [N] to the next flower along a straight line with constant acceleration in 25.0s what is the bird's final velocity as it reaches the next flower
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