a) Use Gauss' law.
4 pi R^2 E = N*e/(epsilono)
N is the number of electrons and e is the electron charge in Coulombs.
E is the electric field strangth in N/C
"epsilon zero" = 8.8554*10^-12 C^2/N m^2
Make sure R is in meters
b) Use the same equation, but use R + 0.1 m in place of R since you are 10 cm farther away.
(a) How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 30.0 cm in diameter to produce an electric field of 1150 N/C just outside the surface of the sphere?
(b) what is the electric field at a point 10.0 cm outside the surface?
ok would I use Guass's law for this one? I am lost... and with the 10 cm..where do I put that in the problem?
2 answers
ok..thank you very much. I thought that is what you would do for part b but I wasn't sure! Thank you!
2 answers