now you have the moles of NH3.
then, there are three atoms of H per molecule, so moles of H is
3*1.468
number of H atoms
3*1.468*avagNumber
a. How many atoms of hydrogen are in 25.0 g of ammonia (NH3)? Use the format 6.02E+23 for 6.02 x 10^23
b. How many atoms of nitrogen are in the same amount of ammonia
I know to find the number of atoms in a gram of a sample you must multiply by 6.02*10^23.
So i multiplied 25*6.02*10^23
ammonias Molecular mass = 17.03
so do i divide 25.0/17.03=1.468 mol NH3
what next
1 answer
1 answer