To calculate the final temperature of the water, we can use the principle of conservation of energy, which states that the total energy of the system remains constant.
Let's denote:
m1 = mass of hot water = 8 kg
T1 = initial temperature of hot water = 85⁰C = 85 + 273 = 358 K
m2 = mass of cold water = 20 kg
T2 = initial temperature of cold water = 30⁰C = 30 + 273 = 303 K
Tf = final temperature of the mixture (to be determined)
According to the principle of conservation of energy:
m1 * T1 + m2 * T2 = (m1 + m2) * Tf
Substitute the given values:
8 * 358 + 20 * 303 = (8 + 20) * Tf
2864 + 6060 = 28 * Tf
8924 = 28 * Tf
Tf = 8924 / 28
Tf = 318 K
Therefore, the final temperature of the water mixture is 318 K.
A hot water tap of a bath delivers water at 85⁰C at a rate of 8Kg per minute. The cold water tap at the bath delivers water at 30⁰C at the rate of 20kg per minutes. If both tapes are at a time of 5 minutes. Calculate the final temperature if the water, ignoring heat loses to the surrounding. In kelvin's
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