To find the final temperature of the water, we can use the principle of conservation of energy, which states that the total energy before the mixing of water is equal to the total energy after the mixing.
The formula we can use is:
(m1 * c1 * (Tf - Ti1) + m2 * c2 * (Tf - Ti2) = 0
Where:
m1 = mass of hot water = 8kg
c1 = specific heat capacity of water = 4.186 J/g°C
Ti1 = initial temperature of hot water = 85°C
m2 = mass of cold water = 20kg
c2 = specific heat capacity of water = 4.186 J/g°C
Ti2 = initial temperature of cold water = 30°C
Tf = final temperature of the mixed water
So we can plug in the values and solve for Tf:
(8 * 4.186 * (Tf - 85) + 20 * 4.186 * (Tf - 30) = 0
(33.488Tf - 2842.48) + (83.72Tf - 2503.2) = 0
117.208Tf - 5345.68 = 0
117.208Tf = 5345.68
Tf = 5345.68 / 117.208
Tf ≈ 45.6°C
Therefore, the final temperature of the mixed water is approximately 45.6°C in Kelvin.
A hot water tap of a bath delivers water at 85⁰C at a rate of 8Kg per minute. The cold water tap at the bath delivers water at 30⁰C at the rate of 20kg per minutes. If both tapes are at a time of 5 minutes. Calculate the final temperature if the water, ignoring heat loses to the surrounding
In kelvin's
1 answer