Recived solar power x time = C*M*deltaT
C = 4184 J/kg*C
M = 1000 kg
deltaT = 35 C
received solar power = 5.8 m^2 * 550 W/m^2 = 3190 Watts
Solve for time required.
It looks like about a half a day.
A hot-water heater is operated by solar power. If the solar collector has an area of 5.8 m2 and the power delivered by sunlight is 550 W/m2, how long will it take to increase the temperature of 1.0 m3 of water from 24°C to 59°C?
1 answer
1 answer